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7x^2+11x=-2
We move all terms to the left:
7x^2+11x-(-2)=0
We add all the numbers together, and all the variables
7x^2+11x+2=0
a = 7; b = 11; c = +2;
Δ = b2-4ac
Δ = 112-4·7·2
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{65}}{2*7}=\frac{-11-\sqrt{65}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{65}}{2*7}=\frac{-11+\sqrt{65}}{14} $
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